document.write( "Question 685725: Four years from now, Daisy will be twice as old as Libeth. Six Years ago she was four times as old as her. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #424543 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Four years from now, Daisy will be twice as old as Libeth. Six Years ago she was four times as old as her. Find their present ages.
\n" ); document.write( "----
\n" ); document.write( "Equations:
\n" ); document.write( "d+4 = 2(L+4)
\n" ); document.write( "d-6 = 4(L-6)
\n" ); document.write( "-----------------
\n" ); document.write( "Rearrange:
\n" ); document.write( "d - 2L = 4
\n" ); document.write( "d - 4L = -18
\n" ); document.write( "---
\n" ); document.write( "Subtract and solve for \"L\":
\n" ); document.write( "2L = 22
\n" ); document.write( "Libeth = 11 years
\n" ); document.write( "========================
\n" ); document.write( "Solve for \"d\" using d -2L = 4
\n" ); document.write( "d -22 = 4
\n" ); document.write( "Daisey = 26 years
\n" ); document.write( "========================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "==============
\n" ); document.write( "
\n" );