document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=61681>Question 61681</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I sent this problem in and made an error on how it has to be solved The system is to be solved by addition. 5x-3y=13 4x-3y=11  Thanks  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42454 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42454\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> is to be solved by addition. <BR>\n" );
document.write( "1st: 5x-3y=13 <BR>\n" );
document.write( "2nd: 4x-3y=11 <BR>\n" );
document.write( "Multiply 2nd by -1 to get:<BR>\n" );
document.write( "3rd: -4x+3y=-11<BR>\n" );
document.write( "Add 3rd to 1st to get:<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( "Substitute into 2nd to solve for \"y\":<BR>\n" );
document.write( "4(2)-3y=11<BR>\n" );
document.write( "-3y=2<BR>\n" );
document.write( "y=-1<BR>\n" );
document.write( "Check in 1st:<BR>\n" );
document.write( "5(2)-3(-1)=13<BR>\n" );
document.write( "10+3=13<BR>\n" );
document.write( "13=13<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );