document.write( "Question 685679: The sum of three numbers is 47. The second numbers is half the first while the third is 1 less than the second. Find the three numbers? \n" ); document.write( "

Algebra.Com's Answer #424527 by Edwin McCravy(20056) $\"\"$ $\"About$

You can put this solution on YOUR website!

\r\n" );
document.write( "First = x\r\n" );
document.write( "second = y\r\n" );
document.write( "third = z\r\n" );
document.write( "\r\n" );
document.write( "Rewrite the problem using those:\r\n" );
document.write( "\r\n" );
document.write( ">>The sum of x,y, and z is 47. \r\n" );
document.write( "y is half of x while z is 1 less than y. \r\n" );
document.write( "Find the three numbers?<<\r\n" );
document.write( "\r\n" );
document.write( "Look at the first part:\r\n" );
document.write( "\r\n" );
document.write( ">>The sum of x,y, and z is 47.<< \r\n" );
document.write( "\r\n" );
document.write( "That says x + y + z = 47\r\n" );
document.write( "\r\n" );
document.write( "Look at the second part:\r\n" );
document.write( "\r\n" );
document.write( ">>y is half of x<<\r\n" );
document.write( "\r\n" );
document.write( "That says y = x\r\n" );
document.write( "\r\n" );
document.write( "Look at the third part\r\n" );
document.write( "\r\n" );
document.write( ">>while z is 1 less than y.<<\r\n" );
document.write( "\r\n" );
document.write( "That says z = y - 1\r\n" );
document.write( "\r\n" );
document.write( "So you have this system of equations:\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Solve that system.  You'll know if you have the right\r\n" );
document.write( "answer because y will be half of x, and z will be one\r\n" );
document.write( "less that y, amd when you add them all you'll get 47.\r\n" );
document.write( "\r\n" );
document.write( "Edwin

\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "

\n" );