document.write( "Question 685596: log5(x-2)= 2 + log5(x-4)
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Algebra.Com's Answer #424506 by lwsshak3(11628) $\"\"$ $\"About$

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log5(x-2)= 2 + log5(x-4)
\n" ); document.write( "log5(x-2)- log5(x-4)=2
\n" ); document.write( "log5[(x-2)/(x-4)]=2
\n" ); document.write( "convert to exponential form
\n" ); document.write( "(x-2)/(x-4)=5^2=25
\n" ); document.write( "x-2=25x-100
\n" ); document.write( "24x=98
\n" ); document.write( "x=4.0833.. \n" ); document.write( "

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