document.write( "Question 685549: An alloy of metals is 25% copper. Another alloy is 50% copper. How much of each alloy should be used to make 1000 grams of an alloy that is 45% copper? \n" ); document.write( "
Algebra.Com's Answer #424485 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! An alloy of metals is 25% copper. Another alloy is 50% copper. How much of each alloy should be used to make 1000 grams of an alloy that is 45% copper? \n" ); document.write( "-------- \n" ); document.write( "Equation: \n" ); document.write( "copper + copper = copper \n" ); document.write( "0.25x + 0.50(1000-x) = 0.45*1000 \n" ); document.write( "---- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "25x + 50*1000 - 50x = 45*1000 \n" ); document.write( "-25x = -5*1000 \n" ); document.write( "x = 200 grams (amt. of 25% copper needed) \n" ); document.write( "---- \n" ); document.write( "1000-x = 800 grams (amt. of 50% copper needed) \n" ); document.write( "=============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |