document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=685188>Question 685188</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This equation involves more than one exponential expression. Solve the equation. Round approximate solutions to four decimal places. This is a logarithm problem.\r<BR>\n" );
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document.write( "6^x = 3^x+1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #424474 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=424474\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6^x = 3^x+1<BR>\n" );
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document.write( "Take the log of both sides to get:<BR>\n" );
document.write( "x*log(6) = (x+1)log(3)<BR>\n" );
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document.write( "x[log(6)-log(3)] = log(3)<BR>\n" );
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document.write( "x = log(3)/[log(6/3)]<BR>\n" );
document.write( "--<BR>\n" );
document.write( "x = log(3)/log(2)<BR>\n" );
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document.write( "x = 1.585..<BR>\n" );
document.write( "===============<BR>\n" );
document.write( "cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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