document.write( "Question 61683This question is from textbook
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document.write( ": THE SECOND ANGLE OF A TRIANGLE IS TWO TIMES AS LARGE AS THE FIRST.THE THIRD ANGLE IS 10DEGREES MORE THAN THE SECOND ANGLE. FIND THE MEASURE OF THE FIRST ANGLE. \n" );
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Algebra.Com's Answer #42444 by joyofmath(189)![]() ![]() ![]() You can put this solution on YOUR website! THE SECOND ANGLE OF A TRIANGLE IS TWO TIMES AS LARGE AS THE FIRST.THE THIRD ANGLE IS 10 DEGREES MORE THAN THE SECOND ANGLE. FIND THE MEASURE OF THE FIRST ANGLE.\r \n" ); document.write( "\n" ); document.write( "Let the first angle = A. \n" ); document.write( "Then, the second angle = 2A. \n" ); document.write( "The third angle = 2A+10. \n" ); document.write( "The 3 angles add up to 180 (for all triangles.)\r \n" ); document.write( "\n" ); document.write( "So, \n" ); document.write( "Or, \n" ); document.write( "Or, \n" ); document.write( "Or, \n" ); document.write( "\n" ); document.write( "Verification:\r \n" ); document.write( "\n" ); document.write( "First angle = 34. \n" ); document.write( "Second angle = 2*first angle = 68. \n" ); document.write( "Third angle = second angle + 10 = 78.\r \n" ); document.write( "\n" ); document.write( "The three angles add up to 34+68+78 = 180. \n" ); document.write( " |