document.write( "Question 61683This question is from textbook
\n" ); document.write( ": THE SECOND ANGLE OF A TRIANGLE IS TWO TIMES AS LARGE AS THE FIRST.THE THIRD ANGLE IS 10DEGREES MORE THAN THE SECOND ANGLE. FIND THE MEASURE OF THE FIRST ANGLE. \n" ); document.write( "
Algebra.Com's Answer #42444 by joyofmath(189)\"\" \"About 
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THE SECOND ANGLE OF A TRIANGLE IS TWO TIMES AS LARGE AS THE FIRST.THE THIRD ANGLE IS 10 DEGREES MORE THAN THE SECOND ANGLE. FIND THE MEASURE OF THE FIRST ANGLE.\r
\n" ); document.write( "\n" ); document.write( "Let the first angle = A.
\n" ); document.write( "Then, the second angle = 2A.
\n" ); document.write( "The third angle = 2A+10.
\n" ); document.write( "The 3 angles add up to 180 (for all triangles.)\r
\n" ); document.write( "\n" ); document.write( "So, \"A%2B2A%2B%282A%2B10%29+=+180\".
\n" ); document.write( "Or, \"5A%2B10+=+180\".
\n" ); document.write( "Or, \"5A=170\".
\n" ); document.write( "Or, \"A=170%2F5+=+34+degrees\".\r
\n" ); document.write( "\n" ); document.write( "Verification:\r
\n" ); document.write( "\n" ); document.write( "First angle = 34.
\n" ); document.write( "Second angle = 2*first angle = 68.
\n" ); document.write( "Third angle = second angle + 10 = 78.\r
\n" ); document.write( "\n" ); document.write( "The three angles add up to 34+68+78 = 180.
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