document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=685432>Question 685432</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hey so I'm doing explorations into variables and I really don't get it so I was wondering if I got this problem right and if I didn't could you please explain what I did wrong and how to fix it? Thank you!<BR>\n" );
document.write( "Problem below.<BR>\n" );
document.write( "2x+1=3x <BR>\n" );
document.write( "I minused 2x from 2x and 3x then I dropped the 1 so now it is 1=1x then what I did is I divided both of them by 1x and then I got x=1 <BR>\n" );
document.write( "Is this right because it doesn't to me? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #424433 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=424433\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x+1=3x <BR>\n" );
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document.write( "Subtract 2x<BR>\n" );
document.write( "1 = x<BR>\n" );
document.write( "x = 1<BR>\n" );
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document.write( "Don't try for a doctorate on it.<BR>\n" );
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