document.write( "Question 685211: Solve the equation 2^(2x) - 2^(x+1)-15=0 \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Find the domain f(x) = log((log((x-1))))
\n" ); document.write( "

Algebra.Com's Answer #424380 by pmatei(79)\"\" \"About 
You can put this solution on YOUR website!
\"2%5E%282x%29+-+2%5E%28x%2B1%29-15=0+++\"\r
\n" ); document.write( "\n" ); document.write( "Re-write it as:\r
\n" ); document.write( "\n" ); document.write( "\"%282%5Ex%29%5E2+-+2%2A2%5Ex+-+15+=+0\"\r
\n" ); document.write( "\n" ); document.write( "Replace \"2%5Ex+=+y\"\r
\n" ); document.write( "\n" ); document.write( "\"y%5E2+-+2y+-+15+=+0\"\r
\n" ); document.write( "\n" ); document.write( "Solve the quadratic in y:\r
\n" ); document.write( "\n" ); document.write( "\"%28y-5%29%28y%2B3%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+5\" and \"y+=+-3\"\r
\n" ); document.write( "\n" ); document.write( "\"2%5Ex+=+-3\" has no solution.\r
\n" ); document.write( "\n" ); document.write( "\"2%5Ex+=+5\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2Aln%282%29+=+ln%285%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28ln%285%29%29%2F%28ln%282%29%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Domain for \"f%28x%29=log%28%28log%28%28x-1%29%29%29%29\"\r
\n" ); document.write( "\n" ); document.write( "The argument of logarithmic function has to be a positive number.\r
\n" ); document.write( "\n" ); document.write( "The first log has as argument log(x-1):\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28x-1%29%29%3E0\"\r
\n" ); document.write( "\n" ); document.write( "Logarithm function is positive if the argument is greater than 1. Logarithm of 1 is zero. And below 1 logarithm function is negative.\r
\n" ); document.write( "\n" ); document.write( "\"x-1%3E1\"\r
\n" ); document.write( "\n" ); document.write( "\"x%3E2\"\r
\n" ); document.write( "\n" ); document.write( "So the domain of f(x) is \"x%3E2\".
\n" ); document.write( "
\n" );