document.write( "Question 61662: anybody know this\r
\n" ); document.write( "\n" ); document.write( "3/5-3x<_1\r
\n" ); document.write( "\n" ); document.write( "thanks
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Algebra.Com's Answer #42436 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve:
\n" ); document.write( "\"3%2F5+-+3x+%3C=+1\" Subtract 3/5 from both sides.
\n" ); document.write( "\"-3x+%3C=+2%2F5\" Divide both sides by -3 and remember to reverse the <=
\n" ); document.write( "\"x+%3E=+2%2F15\"
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