document.write( "Question 685076: The numerator of a fraction is 4 less than its denominator. If you add 1 to both the numerator and the denominator, the resulting fraction is equal to 2/3. What is the original fraction? \n" ); document.write( "
Algebra.Com's Answer #424325 by funmath(2933)\"\" \"About 
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The numerator of a fraction is 4 less than its denominator. If you add 1 to both the numerator and the denominator, the resulting fraction is equal to 2/3. What is the original fraction?\r
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Let the denominator = x

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Then the numerator is 4 less than that: x-4

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If you add 1 to the denominator you have: x+1

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If you add one to the numerator you have: x-4+1 or x-3

\n" ); document.write( "So your algebraic equation is:
\n" ); document.write( "\"%28x-3%29%2F%28x%2B1%29=2%2F3\"
\n" ); document.write( "Cross Multiply:
\n" ); document.write( "\"3%28x-3%29=2%28x%2B1%29\"
\n" ); document.write( "\"3x-9=2x%2B2\"
\n" ); document.write( "\"3x-2x-9=2x-2x%2B2\"
\n" ); document.write( "\"x-9=2\"
\n" ); document.write( "\"x-9%2B9=2%2B9\"
\n" ); document.write( "\"x=11\"
\n" ); document.write( "Your denominator is x=11
\n" ); document.write( "Your numerator is: x-4=11-4=7
\n" ); document.write( "The original fraction is: \"highlight%287%2F11%29\"\r
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Do a sanity check...if you add 1 to the numerator and denominator, does it indeed reduce to 2/3's?
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