document.write( "Question 684828: Can someone help me solve the following equation. I've tried it three different ways and still keep getting it wrong.\r
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document.write( "Write an equation of the line containing the given point and parallel to the given line. (8,-3); 3x + 2y = 7\r
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document.write( "-2y=-3x+7\r
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document.write( "y= 3/2x - 7/2\r
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document.write( "y-(-3)= 3/2 (x-8)
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document.write( "y+3=3/2x - 24/2
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document.write( "y=3/2x - 24/2 - 3
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document.write( "y=3/2x - 21/2\r
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document.write( "I don't know where I went wrong. Please assist. Thank you \n" );
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Algebra.Com's Answer #424289 by ReadingBoosters(3246)![]() ![]() ![]() You can put this solution on YOUR website! Start with 3x + 2y = 7 \n" ); document.write( "solve for y, subtract 3x from both sides \n" ); document.write( "2y = -3x + 7 \n" ); document.write( "y = \n" ); document.write( "... \n" ); document.write( "slope is \n" ); document.write( "Parallel lines have the same slope. \n" ); document.write( "... \n" ); document.write( "Using slope and the point, \n" ); document.write( "y - -3 = \n" ); document.write( "y + 3 = \n" ); document.write( "y +3 = \n" ); document.write( "y = \n" ); document.write( " \n" ); document.write( "... \n" ); document.write( "... \n" ); document.write( "First error was in solving for y, when you subtract the 3x the 2y remains positive. \n" ); document.write( "Second error was in subtracting fractions \n" ); document.write( "if you were on the right track, \n" ); document.write( "..................... \n" ); document.write( "Have more questions? \n" ); document.write( "Email: HomeworkHelpers@readingboosters.com \n" ); document.write( "Delighted to help. \n" ); document.write( "-Reading Boosters \n" ); document.write( "Website: www.MyHomeworkAnswers.com \n" ); document.write( "Wanting for others what we want for ourselves. \n" ); document.write( " \n" ); document.write( " |