document.write( "Question 684436: What is 2x+y=5and 3x-2y=4 by using elimination to solve the system of equation? \n" ); document.write( "
Algebra.Com's Answer #424276 by ReadingBoosters(3246)\"\" \"About 
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Multiply the first equation by 2
\n" ); document.write( "2(2x+y=5) to get 4x + 2y = 10
\n" ); document.write( "add the second equation 3x-2y=4
\n" ); document.write( "4x + 3x + 2y + -2y = 10 + 4
\n" ); document.write( "7x = 14
\n" ); document.write( "x = 2
\n" ); document.write( "...
\n" ); document.write( "Multiply the first equation by 3 and the second equation by -2 then add
\n" ); document.write( "3(2x+y=5) to get 6x + 3y = 15
\n" ); document.write( "-2(3x-2y=4) to get -6x + 4y = -8
\n" ); document.write( "add them
\n" ); document.write( "6x + -6x + 3y + 4y = 15 + -8
\n" ); document.write( "7y = 7
\n" ); document.write( "y = 1
\n" ); document.write( "...
\n" ); document.write( "\"highlight_green%28x=2%29\" and \"highlight_green%28y=1%29\"
\n" ); document.write( "(2, 1) is the solution
\n" ); document.write( "...
\n" ); document.write( "check
\n" ); document.write( "2(2) + 1 = 5
\n" ); document.write( "4 + 1 = 5
\n" ); document.write( "5 = 5
\n" ); document.write( "Correct
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