document.write( "Question 61639This question is from textbook Algebra 1
\n" ); document.write( ": Please help me write an equation of the line that has the given x-intercept and slope:\r
\n" ); document.write( "\n" ); document.write( " x-intercept = 2, m = -2/3.
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Algebra.Com's Answer #42426 by Earlsdon(6294)\"\" \"About 
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You can start by writing the general slope-intercept form of a linear equation:
\n" ); document.write( "y = mx + b where: m is the slope and b is the y-intercept. You have been given the slope, m = -2/3, so you can write:
\n" ); document.write( "\"y+=+%28-2%2F3%29x+%2B+b\" So far, so good! But now you need to find the value of b, the y-intercept. You can do this because you have been given the x-intercept, x = 2 and because you know that the x-intercept is where the line intersects (crosses) the x-axis and the y-coordinate at this point is y = 0.
\n" ); document.write( "So the x-intercept has the coordinates: (2, 0). This allows you to find b,in the equation because you can substitute the x- and y-coordinates of this point into the equation and solve for b.\r
\n" ); document.write( "\n" ); document.write( "\"0+=+%28-2%2F3%292+%2B+b\" Solving this for b, you get:
\n" ); document.write( "\"b+=+4%2F3\" So now you can write the final equation of the line in the slope-intercept form: y = mx + b\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%28-2%2F3%29x+%2B+4%2F3\"
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