document.write( "Question 684758: $\"sqrt%283x%2B10%29=x%2B2\"$ \n" ); document.write( "

Algebra.Com's Answer #424197 by ReadingBoosters(3246) $\"\"$ $\"About$

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$\"sqrt%283x%2B10%29+=+x%2B2\"$
\n" ); document.write( "Square both sides to \"undo\" the square root, since they are inverse operations.
\n" ); document.write( "...
\n" ); document.write( " $\"sqrt%283x%2B10%29%5E2+=+%28x%2B2%29%5E2\"$
\n" ); document.write( "3x+10 = (x+2)^2
\n" ); document.write( " $\"3x+%2B+10+=+x%5E2+%2B+4x+%2B+4\"$
\n" ); document.write( " $\"0+=+x%5E2+%2B+4x+-+3x+%2B+4+-+10\"$
\n" ); document.write( " $\"0+=+x%5E2+%2B+x+-+6\"$
\n" ); document.write( "(x+3)(x-2) = 0
\n" ); document.write( "x+3 = 0
\n" ); document.write( "x = -3
\n" ); document.write( "AND
\n" ); document.write( "x-2=0
\n" ); document.write( "x = 2
\n" ); document.write( "...
\n" ); document.write( " $\"sqrt%283x%2B10%29+=+x%2B2\"$
\n" ); document.write( "...
\n" ); document.write( " $\"sqrt%283%28-3%29%2B10%29+=+sqrt%28-9%2B10%29+=+sqrt%281%29+=+1\"$
\n" ); document.write( "-3 + 2 = -1
\n" ); document.write( " $\"1%3C%3E-1\"$
\n" ); document.write( "x = -3 is not a solution
\n" ); document.write( " $\"sqrt%283%282%29%2B10%29+=+sqrt%286%2B10%29+=+sqrt%2816%29+=+4\"$
\n" ); document.write( "2+2 = 4
\n" ); document.write( " $\"4=4\"$
\n" ); document.write( "x = 2 is a solution
\n" ); document.write( ".....................
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