document.write( "Question 684698: If Y=80 when X=32, find X when Y=100
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Algebra.Com's Answer #424180 by Alan3354(69443)\"\" \"About 
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If Y=80 when X=32, find X when Y=100
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\n" ); document.write( "Not enough info.
\n" ); document.write( "it might be
\n" ); document.write( "y = x + 48
\n" ); document.write( "y = x*2.5
\n" ); document.write( "y = 2x + 16
\n" ); document.write( "y = 20sqrt(x/2)
\n" ); document.write( "or an infinite # of other possibilities.\r
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