document.write( "Question 61621: A ball is thrown vertically upward from the top of a building 112 feet tall with an initial velocity of 96 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s=112+96t-16t^2. After how many seconds will the ball pass the top of the building on its way down? \r
\n" ); document.write( "\n" ); document.write( "I BELIEVE I WOULD USE THE Distance=Rate X Time
\n" ); document.write( "Is that right? Is this how I would start it?
\n" ); document.write( "112+96t-16t^2=r x t.....i got stuck
\n" ); document.write( "

Algebra.Com's Answer #42418 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
The use of the distance formula, d = rt, is not appropriate for this kind of problem. The reason is the distance formula applies in cases of constant motion (speed) whereas this problem involves acceleration (due to gravity).
\n" ); document.write( "You have the appropriate function of distance (really height) as a function of time.
\n" ); document.write( " The question here is...when will the ball reach a height (distance) of 112 feet after being thrown upward?
\n" ); document.write( "To find out, wou want to set the given function of s(t) equal to 112 ft. and solve for the time, t.\r
\n" ); document.write( "\n" ); document.write( "\"112+%2B+96t+-+16t%5E2+=+112\" Subtract 112 from both sides.
\n" ); document.write( "\"96t+-+16t%5E2+=+0\" Factor out a t.
\n" ); document.write( "\"t%2896+-+16t%29+=+0\" Apply the zero product principle.
\n" ); document.write( "\"t+=+0\" and \"96+-+16t+=+0\"
\n" ); document.write( "At t = 0 seconds, the ball is at 112 feet because that the initial height of the throw.
\n" ); document.write( "\"96+-+16t+=+0\" Add 16t to both sides.
\n" ); document.write( "\"96+=+16t\" Divide both sides by 16.
\n" ); document.write( "\"t+=+6\"
\n" ); document.write( "The ball will be at 112 feet again in 6 seconds.
\n" ); document.write( "
\n" );