document.write( "Question 684570: Can you please help me with this:\r
\n" ); document.write( "\n" ); document.write( "Solve the equation:
\n" ); document.write( "3x^2-8x=0\r
\n" ); document.write( "\n" ); document.write( "Here is what i have:
\n" ); document.write( "-8+_ sqrt (64-4(3)(0))/2(3)
\n" ); document.write( "-8 +- sqrt 64-0/6
\n" ); document.write( "-8 +- 8/6
\n" ); document.write( "then -8-8/6 would be x=-16/6
\n" ); document.write( "and -8+8/6 would be x= 0/6
\n" ); document.write( "so it would be x=-16/6 x=0/6
\n" ); document.write( "Is this remotely close? Thanks! \n" ); document.write( "

Algebra.Com's Answer #424142 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
Can you please help me with this:
\n" ); document.write( "Solve the equation:
\n" ); document.write( "3x^2 - 8x = 0
\n" ); document.write( "You are making this much harder than it is, just factor out x, and you have
\n" ); document.write( "x(3x - 8) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "x = 0
\n" ); document.write( "and
\n" ); document.write( "3x = 8
\n" ); document.write( "x = 8/3
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check in the original equation
\n" ); document.write( "3(8/3)^2 - 8(8/3) = 0
\n" ); document.write( "3(64/9) - (64/3) = 0
\n" ); document.write( "cancel 3 into 9
\n" ); document.write( "(64/3) - 64/9) = 0 \n" ); document.write( "

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