document.write( "Question 684225: The volume of a solid object varies jointly with the length of the height and inversely with the square root of the width of the object. If the volume is 30 m^3 when the length = 20 meters, width = 9 meters and the height = 4 meters, find the volume in (m^3) of the solid object when the width is 16 meters and the length is 44 meters and the hight is 8 meters. \r
\n" ); document.write( "\n" ); document.write( "Here is what I understand. V = K (l)(h)/square root
\n" ); document.write( "I plugged in 30m^3 = K (20)(4)/Square root of 9
\n" ); document.write( "Then I got 30m^3 = K800 and then I got stuck from there. I don't know whether to divide 800 on both sides or 30. I think its 800, so that K = 30^m/800. After that, the problem seemed like a mess, because the answer is actually 99m^3 and I got 33m^3/20, because I did something totally stupid. What am I doing wrong? Thank you in advance for your help.
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Algebra.Com's Answer #424109 by MathTherapy(10555)\"\" \"About 
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The volume of a solid object varies jointly with the length of the height and inversely with the square root of the width of the object. If the volume is 30 m^3 when the length = 20 meters, width = 9 meters and the height = 4 meters, find the volume in (m^3) of the solid object when the width is 16 meters and the length is 44 meters and the hight is 8 meters. \r
\n" ); document.write( "\n" ); document.write( "Here is what I understand. V = K (l)(h)/square root
\n" ); document.write( "I plugged in 30m^3 = K (20)(4)/Square root of 9
\n" ); document.write( "Then I got 30m^3 = K800 and then I got stuck from there. I don't know whether to divide 800 on both sides or 30. I think its 800, so that K = 30^m/800. After that, the problem seemed like a mess, because the answer is actually 99m^3 and I got 33m^3/20, because I did something totally stupid. What am I doing wrong? Thank you in advance for your help.\r
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\n" ); document.write( "\n" ); document.write( "Since volume varies jointly with the height and length, and inversely with the square root of the width, then: \"V+=+kLH%2Fsqrt%28W%29\"
\n" ); document.write( "Therefore, with V = 30, L = 20, H = 4, and W = 9, then \"V+=+kLH%2Fsqrt%28W%29\" becomes: \"30+=+k%2820%29%284%29%2Fsqrt%289%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"30+=+80k%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "80k = 90 ------ Cross-multiplying\r
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\n" ); document.write( "\n" ); document.write( "\"k+=+90%2F80\", or \"k+=+9%2F8\"\r
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\n" ); document.write( "\n" ); document.write( "Now, with \"k+=+9%2F8\", and with W = 16, L = 44, and H = 8, then V (volume) = \"%289%2F8%29%2844%29%288%29%2Fsqrt%2816%29\" ------ \"396%2F4\", or \"highlight_green%2899m%5E3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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