document.write( "Question 684401: A telephone pole was bent over at the point 4/9 of the distance from its base to the top. The top of the pole reaches a point on the ground 9 meters from the base of the pole (thus forming a triangle with the ground). What was the original height of the pole? \n" ); document.write( "

Algebra.Com's Answer #424092 by mananth(16946) $\"\"$ $\"About$

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let the length of pole be x
\n" ); document.write( "4x/9 is erect and 5x/9 is the bent portion which is the hypotenuse of the triangle formed.
\n" ); document.write( "distance from ground = 9 m\r
\n" ); document.write( "\n" ); document.write( "Using Pythagoras theorem\r
\n" ); document.write( "\n" ); document.write( " $\"9%5E2%2B%284x%2F9%29%5E2=+%285x%2F9%29%5E2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"81%2B16x%5E2%2F81+=+25x%5E2%2F81\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"25x%5E2%2F81+-16x%5E2%2F81+=+81%0D%0A%0D%0A%7B%7B%7B%2825x%5E2-16x%5E2%29%2F81+=+81\"$ \r
\n" ); document.write( "\n" ); document.write( "multiply equation by 81\r
\n" ); document.write( "\n" ); document.write( " $\"9x%5E2=+81%2A81\"$
\n" ); document.write( "/9
\n" ); document.write( "x^2= 81*81/9\r
\n" ); document.write( "\n" ); document.write( "x^2=81*9\r
\n" ); document.write( "\n" ); document.write( "x= +/- 9*3
\n" ); document.write( "x= 27 ignore negative value.\r
\n" ); document.write( "\n" ); document.write( "Length of pole = 27m\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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