document.write( "Question 684328: For each right triangle find all the missing values of the side lengths and angle measures.Show your work\r
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document.write( "a) Triangle PQR is right angled at Q , PQ is 24 cm, RQ is 10 cm , PQ is the hypotenuse which is unknown.\r
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document.write( "b) Triangle PRQ is right angled at R, PQ is 30 mm , RQ is 40 mm , PQ is 50 mm.\r
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document.write( "c) Triangle QRP is right angled at R , angle of P is 60 degrees, QP is 20 cm.\r
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document.write( "can you please explain this to me? thanks in advance\r
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document.write( "d) Triangle PQR is right angled at Q , QR is 1.125 dm, PR is 5.125 dm. \n" );
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Algebra.Com's Answer #424053 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! For each right triangle find all the missing values of the side lengths and angle measures.Show your work \n" ); document.write( "a) Triangle PQR is right angled at Q , PQ is 24 cm, RQ is 10 cm , PQ is the hypotenuse which is unknown. \n" ); document.write( "PQ = sqrt[24^2+10^2] = sqrt(576] = 26 \n" ); document.write( "--------------------------------------------------- \n" ); document.write( "b) Triangle PRQ is right angled at R, PQ is 30 mm , RQ is 40 mm , PQ is 50 mm. \n" ); document.write( "P is the angle opposite RQ \n" ); document.write( "PQ is opposite R and is the hypotenuse \n" ); document.write( "So P = sin^-1(40/50) = 53.13 degrees \n" ); document.write( "And Q = sin^-1(30/50) = 36.87 degrees\r \n" ); document.write( "\n" ); document.write( "----------------------------- \n" ); document.write( "c) Triangle QRP is right angled at R , angle of P is 60 degrees, QP is 20 cm. \n" ); document.write( "can you please explain this to me? thanks in advance \n" ); document.write( "Draw the picture. \n" ); document.write( "You have a right triangle with \n" ); document.write( "hypotenuse is side opposite right angle R which is QP = 20 cm \n" ); document.write( "P = 60 degrees is the angle opposite QR \n" ); document.write( "Q = 90-60 = 30 degrees \n" ); document.write( "------ \n" ); document.write( "QR is side opposite P, so sin(P) = QR/QP ; sin(60) = QR/20 ; \n" ); document.write( "QR = 20*sin(60) = 17.32 \n" ); document.write( "PR is side opposite Q which is 30 degrees \n" ); document.write( "PR = (1/2)*hypotenuse = (1/2)*20 = 10 cm \n" ); document.write( "-------------------------------- \n" ); document.write( "--------------------------- \n" ); document.write( "d) Triangle PQR is right angled at Q , QR is 1.125 dm, PR is 5.125 dm. \n" ); document.write( "Draw the picture and see if you can determine: \n" ); document.write( "angle P = \n" ); document.write( "angle R = \n" ); document.write( "side PQ = \n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================== \n" ); document.write( " \n" ); document.write( " |