document.write( "Question 684307: \r
\n" ); document.write( "\n" ); document.write( "The length of the rectangle is 1 inches more then the width. The area is 30 square inches. Find the dimensions.
\n" ); document.write( "

Algebra.Com's Answer #424052 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
A=LW
\n" ); document.write( "L=W+1
\n" ); document.write( "30=(W+1)W
\n" ); document.write( "30=W^2+W
\n" ); document.write( "W^2+W-30=0
\n" ); document.write( "(W+6)(W-5)=0
\n" ); document.write( "W-5=0
\n" ); document.write( "W=5 ANS. FOR THE WIDTH.
\n" ); document.write( "L=5+1=6 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF
\n" ); document.write( "30=6*5
\n" ); document.write( "30=30
\n" ); document.write( "
\n" );