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document.write( "the length of a rectangle is 2.8 cm more than 4 times the width. if the perimeter of the rectangle is 38.6 cm, what are its dimensions? \n" );
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Algebra.Com's Answer #424042 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "L=2.8+4W\r \n" ); document.write( "\n" ); document.write( "38.6=2(2.8+4W)+2W \n" ); document.write( "38.6=5.6+8W+2W \n" ); document.write( "38.6-5.6=10W \n" ); document.write( "10W=33 \n" ); document.write( "W=33/10 \n" ); document.write( "W=3.3 CM. FOR THE WIDTH. \n" ); document.write( "L=2.8+4*3.3 \n" ); document.write( "L=2.8+13.2 \n" ); document.write( "L=16 CM FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "38.6=2*16+2*3.3 \n" ); document.write( "38.6=32+6.6 \n" ); document.write( "38.6=38.6 \n" ); document.write( " \n" ); document.write( " |