document.write( "Question 684332: \r
\n" ); document.write( "\n" ); document.write( "the length of a rectangle is 2.8 cm more than 4 times the width. if the perimeter of the rectangle is 38.6 cm, what are its dimensions?
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Algebra.Com's Answer #424042 by checkley79(3341)\"\" \"About 
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P=2L+2W
\n" ); document.write( "L=2.8+4W\r
\n" ); document.write( "\n" ); document.write( "38.6=2(2.8+4W)+2W
\n" ); document.write( "38.6=5.6+8W+2W
\n" ); document.write( "38.6-5.6=10W
\n" ); document.write( "10W=33
\n" ); document.write( "W=33/10
\n" ); document.write( "W=3.3 CM. FOR THE WIDTH.
\n" ); document.write( "L=2.8+4*3.3
\n" ); document.write( "L=2.8+13.2
\n" ); document.write( "L=16 CM FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "38.6=2*16+2*3.3
\n" ); document.write( "38.6=32+6.6
\n" ); document.write( "38.6=38.6
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