document.write( "Question 684340: Find the equation of a straight line l1 which is perpendicular to l2:2x+3y-1=0 at the meeting point of l2 with the y-axis. \n" ); document.write( "

Algebra.Com's Answer #424033 by stanbon(75887) $\"\"$ $\"About$

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Find the equation of a straight line l1 which is perpendicular to l2:2x+3y-1=0 at the meeting point of l2 with the y-axis.
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\n" ); document.write( "Determine the slope of the given line:
\n" ); document.write( "2x + 3y - 1 = 0
\n" ); document.write( "3y = -2x+1
\n" ); document.write( "y = (-2/3)x + (1/3)
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\n" ); document.write( "Slope = -2/3
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\n" ); document.write( "Any line perpendicular to it must have a slope of 3/2
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\n" ); document.write( "Equation Form: y = mx + b
\n" ); document.write( "You know m = 3/2 and y = 0 when x = 12
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\n" ); document.write( "Solve for \"b\":
\n" ); document.write( "0 = (3/2)12 + b
\n" ); document.write( "b = -18
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\n" ); document.write( "Equation:
\n" ); document.write( "y = (3/2)x - 18
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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