document.write( "Question 1378: A ship on the ocean surface detects a sunken ship on the ocean floor at an angle of depression of 50 degrees. The distance between the ship on the surface and the sunken ship on the ocean floor is 200 meters. If the ocean floor is level in this area how far above the ocean floor to the nearest meter is the ship on the surface. \n" ); document.write( "
Algebra.Com's Answer #424 by khwang(438)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " Let A be the ship onthe ocean surface,andBbe the sunken ship \n" ); document.write( " as diagram below. \n" ); document.write( " A--------C \n" ); document.write( " |\ \n" ); document.write( " | \ \n" ); document.write( " | \ \n" ); document.write( " | \ \n" ); document.write( " | \ \n" ); document.write( " | \ \n" ); document.write( " P B Angle BAC is the angle of depression \n" ); document.write( " \n" ); document.write( " Since AB = 200 m and Angle ABP = Angle BAC = 50 deg\r \n" ); document.write( "\n" ); document.write( " Hence, the vertical distance AP = 200 sin 50 = 153 meter...Answer \n" ); document.write( " \n" ); document.write( " |