document.write( "Question 684100: a chemist has one solution that is 25% acid and a second one that is 50% acid. how many liters of each should be mixed to get 10 liters of a solution that is 40% acid? \n" ); document.write( "
Algebra.Com's Answer #423973 by ankor@dixie-net.com(22740)\"\" \"About 
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a chemist has one solution that is 25% acid and a second one that is 50% acid.
\n" ); document.write( " how many liters of each should be mixed to get 10 liters of a solution that is 40% acid?
\n" ); document.write( ":
\n" ); document.write( "Let x = amt of 50% acid
\n" ); document.write( "the resulting amt is to be 10 liters, therefore
\n" ); document.write( "(10-x) = amt of 25% acid
\n" ); document.write( ":
\n" ); document.write( "A typical mixture equation
\n" ); document.write( ":
\n" ); document.write( ".50x + .25(10-x) = .40(10)
\n" ); document.write( ".50x + 2.5 - .25x = 4
\n" ); document.write( ".50x - .25x = 4 - 2.5
\n" ); document.write( ".25x = 1.5
\n" ); document.write( "x = 1.5/.25
\n" ); document.write( "x = 6 liters of 50% solution
\n" ); document.write( "and
\n" ); document.write( "10 - 6 = 4 liters of 25% solution
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