document.write( "Question 684100: a chemist has one solution that is 25% acid and a second one that is 50% acid. how many liters of each should be mixed to get 10 liters of a solution that is 40% acid? \n" ); document.write( "
Algebra.Com's Answer #423973 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a chemist has one solution that is 25% acid and a second one that is 50% acid. \n" ); document.write( " how many liters of each should be mixed to get 10 liters of a solution that is 40% acid? \n" ); document.write( ": \n" ); document.write( "Let x = amt of 50% acid \n" ); document.write( "the resulting amt is to be 10 liters, therefore \n" ); document.write( "(10-x) = amt of 25% acid \n" ); document.write( ": \n" ); document.write( "A typical mixture equation \n" ); document.write( ": \n" ); document.write( ".50x + .25(10-x) = .40(10) \n" ); document.write( ".50x + 2.5 - .25x = 4 \n" ); document.write( ".50x - .25x = 4 - 2.5 \n" ); document.write( ".25x = 1.5 \n" ); document.write( "x = 1.5/.25 \n" ); document.write( "x = 6 liters of 50% solution \n" ); document.write( "and \n" ); document.write( "10 - 6 = 4 liters of 25% solution \n" ); document.write( " |