document.write( "Question 684180: Hello tutor, can you help me on this problem? Thank you!\r
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document.write( "Tom is now 25 years older than his son. In 10 years, Tom will be 5 years younger than 3 times his son's age. How old is Tom now?\r
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document.write( "Let Tom be N years old now.\r
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document.write( "Thank you again! :) \n" );
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Algebra.Com's Answer #423965 by lmeeks54(111)![]() ![]() You can put this solution on YOUR website! Let T = age of Tom now \n" ); document.write( "Let S = age of Tom's son now \n" ); document.write( "~ ~ ~ \n" ); document.write( "Given: \n" ); document.write( "T = S + 25 (Tom is 25 yrs older than his son is now) \n" ); document.write( "T + 10 = 3S - 5 (in 10 yrs, Tom will be 5 yrs younger than 3x his son's age) \n" ); document.write( "~ ~ ~ \n" ); document.write( "Method: with 2 equations and 2 variables, express one of the variables in terms of the other and solve: \n" ); document.write( "~ ~ ~ \n" ); document.write( "Take the equation with T = S + 25 and plug S + 25 into the 2nd equation for T: \n" ); document.write( "~ ~ ~ \n" ); document.write( "(S + 25) + 10 = 3S - 5 \n" ); document.write( "~ ~ ~ \n" ); document.write( "Put all the S terms on one side and group all like-terms on the other: \n" ); document.write( "~ ~ ~ \n" ); document.write( "S + 35 = 3S - 5 \n" ); document.write( "40 = 2S \n" ); document.write( "~ ~ ~ \n" ); document.write( "divide both sides by 2: \n" ); document.write( "~ ~ ~ \n" ); document.write( "20 = S \n" ); document.write( "T = S + 25 \n" ); document.write( "~ ~ ~ \n" ); document.write( "Answer: \n" ); document.write( "T = 45 \n" ); document.write( "S = 20 \n" ); document.write( "~ ~ ~ \n" ); document.write( "Lee \n" ); document.write( " \n" ); document.write( " |