document.write( "Question 684124: Please help me factor this completly.
\n" ); document.write( "\"-5x%5E5-50x%5E4-200x%5E3-400x%5E2-400x-160\"\r
\n" ); document.write( "\n" ); document.write( "Thank you so much! \n" ); document.write( "
Algebra.Com's Answer #423934 by Onmyoji.S(32)\"\" \"About 
You can put this solution on YOUR website!
Please help me factor this completly.
\n" ); document.write( "\"-5x%5E5-50x%5E4-200x%5E3-400x%5E2-400x-160\"
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\n" ); document.write( "\n" ); document.write( "-5x^5-50x^4-200x^3-400x^2-400x-160
\n" ); document.write( "=（-5x^5-50x^4）+(-200x^3-400x^2)+(-400x-160)
\n" ); document.write( "=-5x^4(x+10)-200x^2(x+2)-80(5x+2)
\n" ); document.write( "=(-5x^4-200x^2-80)(x+10)(x+2)(5x+2)
\n" ); document.write( "=-5(x^4+40x^2+16)(x+10)(x+2)(5x+2)
\n" ); document.write( "simplify:(x^4+40x^2+16)
\n" ); document.write( "x^4+40x^2=-16 ----completing the square:(40/2)^2=400
\n" ); document.write( "x^4+40x^2+400=-16
\n" ); document.write( "(x^2+20)^2=-16+400
\n" ); document.write( "(x^2+20)^2=384
\n" ); document.write( "(x^2+20)-384
\n" ); document.write( "=-5(x^2+20)-384(x+10)(x+2)(5x+2)
\n" ); document.write( "=-5-384(x^2-20)(x+10)(x+2)(5x+2)
\n" ); document.write( "=-389(x^2-20)(x+10)(x+2)(5x+2)\r
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