document.write( "Question 61512: Use calculus to determine the relative extrema of f(x)=x-lnx\r
\n" );
document.write( "\n" );
document.write( "Find the equation of the tangent line at x=1\r
\n" );
document.write( "\n" );
document.write( "please help, i'm so confused! \n" );
document.write( "
Algebra.Com's Answer #42393 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! Use calculus to determine the relative extrema of f(x)=x-lnx\r \n" ); document.write( "\n" ); document.write( "Find the equation of the tangent line at x=1 \n" ); document.write( "To find the relative extrema take the first derivative and find the numbers that make it 0 or undefined as long as the original function is defined there. \n" ); document.write( "f'(x)= \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "It's undefined at 0, but so is the original function, so we can't have a relative extrema there. \n" ); document.write( "f(1)=1-ln(1) \n" ); document.write( "f(1)=1-0 \n" ); document.write( "f(1)=1 \n" ); document.write( "There is a relative extrema at (1,1) \n" ); document.write( "f''(x)= \n" ); document.write( "f''(1)= \n" ); document.write( "f''(1)=1 The second derivative is positive, so it's a local min. \n" ); document.write( ": \n" ); document.write( "f'(1)=1-1/1 \n" ); document.write( "f'(1)=1-1 \n" ); document.write( "f'(1)=0 The slope of the tangent line is 0. \n" ); document.write( ": \n" ); document.write( "We already found that f(1)=1 \n" ); document.write( "The equation of line with the slope of 0 going through the point (1,1) is \n" ); document.write( "Happy Calculating!!! \n" ); document.write( " |