document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=516737>Question 516737</A>: <I><SPAN STYLE=\"word-break: break-all;\"> angles 1 and 2 are complementary. If angle 1 = 3x+2 and angle 2 =2x+3 find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #423903 by </B><A HREF=/tutors/aboutme.mpl?userid=randyjoseph7><B>randyjoseph7(13)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=randyjoseph7><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=randyjoseph7><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=423903\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> complimentary angles = 90 degrees therefore\r<BR>\n" );
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document.write( "<1=3x+2 + <2=2x+3 = 90\r<BR>\n" );
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document.write( "5x+5=90<BR>\n" );
document.write( " we want to get x alone so subtract +5 from both sides\r<BR>\n" );
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document.write( "5x=90-5<BR>\n" );
document.write( "5x=85\r<BR>\n" );
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document.write( "divide 5 by both sides to get x\r<BR>\n" );
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document.write( "5x = 85<BR>\n" );
document.write( "__   __<BR>\n" );
document.write( "5     5\r<BR>\n" );
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document.write( "x=17\r<BR>\n" );
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document.write( "90-17=73 degrees<BR>\n" );
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