document.write( "Question 7628: The amount of a radioactive tracer remaining after t days is given
\n" ); document.write( "by A = A0 e^–0.18t, where A0 is the starting amount at the beginning of
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Algebra.Com's Answer #4239 by prince_abubu(198)\"\" \"About 
You can put this solution on YOUR website!
So the A-final will be 40 grams, right, and you want to know how much you started with 3 days ago? Let's see:\r
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\n" ); document.write( "\n" ); document.write( "\"+40+=+A%5B0%5De%5E%28-0.18%283%29%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"+40+=+A%5B0%5De%5E%28-0.54%29+\" <---- simplified.\r
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\n" ); document.write( "\n" ); document.write( "\"+%2840%2Fe%5E%28-0.54%29%29+=+A%5B0%5D+\" <---- divide both sides by \"+e%5E%28-0.54%29+\".\r
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\n" ); document.write( "\n" ); document.write( "\"+68.64+=+A%5B0%5D+\" <---- Calculate using calculator. You should get approximately 68.64 grams three days ago.\r
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\n" ); document.write( "\n" ); document.write( "Calculators differ a lot when it comes to how to punch buttons to compute \"e to the something\" power, so I can't really explain this part to you.
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