document.write( "Question 683986: QUESTION: PERMUTATION / COMBINATION\r
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document.write( "Three boy's A,B, and C rode a minibus that has seven vacant seats on each side. How many ways can they be seated if B insisted on sitting on the left side.\r
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document.write( "Ans. 1092 ( help me pls. with the solution) \n" );
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Algebra.Com's Answer #423873 by Edwin McCravy(20054)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "We can choose a seat on the left for for B in 7 ways.\r\n" ); document.write( "\r\n" ); document.write( "That leaves 13 seats (6 on the left and 7 on the right)\r\n" ); document.write( "\r\n" ); document.write( "For each of the 7 ways we can choose a seat for B, we\r\n" ); document.write( "\r\n" ); document.write( "can choose a seat for A in 13 ways. That's 7×13 or 91 ways\r\n" ); document.write( "to seat B and A.\r\n" ); document.write( "\r\n" ); document.write( "That leaves 12 vacant seats.\r\n" ); document.write( "\r\n" ); document.write( "For each of those 91 ways we can seat B and A, we can seat C\r\n" ); document.write( "in any one of those remaining 12 seats.\r\n" ); document.write( "\r\n" ); document.write( "So that's a total of 12×91 = 1092 ways.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |