document.write( "Question 683984: how can u solve this \r
\n" ); document.write( "\n" ); document.write( "1.) 2 (sqrt of x+4) = 5
\n" ); document.write( "2.) 3t (sqrt of x-1) = 5
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Algebra.Com's Answer #423857 by ReadingBoosters(3246)\"\" \"About 
You can put this solution on YOUR website!
1.
\n" ); document.write( "\"2sqrt%28x%2B4%29=5\" ==> divide both sides by 2
\n" ); document.write( "\"sqrt%28x%2B4%29+=+5%2F2\" ==> square both sides to \"undo\" the square root
\n" ); document.write( "\"sqrt%28x%2B4%29%5E2+=+%285%2F2%29%5E2\"
\n" ); document.write( "x+4 = \"25%2F4\"==> subtract 4 from both sides
\n" ); document.write( "x = \"25%2F4+-+4+=+25%2F4+-+4%284%2F4%29+=+25%2F4+-+16%2F4+=+highlight_green%289%2F4%29\"
\n" ); document.write( "...
\n" ); document.write( "2. if you are solving for x
\n" ); document.write( "\"3t%28sqrt%28x-1%29%29+=+5\" ==> divide both sides by 3t
\n" ); document.write( "\"sqrt%28x-1%29+=+5%2F3t\" ==> square both sides
\n" ); document.write( "\"sqrt%28x-1%29%5E2+=+%285%2F%283t%29%29%5E2\"
\n" ); document.write( "x - 1 = \"25%2F%289t%5E2%29\"
\n" ); document.write( "x =
\n" ); document.write( ".....................
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