document.write( "Question 683948: how can i find rule for sequances 100,99,95,86 \n" ); document.write( "
Algebra.Com's Answer #423842 by Edwin McCravy(20059)\"\" \"About 
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100,99,95,86
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document.write( "Start with \r\n" );
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document.write( "100, the first term.\r\n" );
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document.write( "100-1² = 100-1 = 99, the second term.\r\n" );
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document.write( " 99-2² =  99-4 = 95, the third term.\r\n" );
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document.write( " 95-3² =  95-9 = 86, the forth term.\r\n" );
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document.write( "Rule for getting the (n+1)st term:\r\n" );
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document.write( "Take the nth term and subtract n squared.\r\n" );
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document.write( "So the recursion formula is\r\n" );
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document.write( "a1 = 100, an+1 = an - n²\r\n" );
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document.write( "The general formula is\r\n" );
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document.write( "an = 100-\"%28n%2A%28n-1%29%282n-1%29%29%2F6\"\r\n" );
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document.write( "That's found by more advanced methods.\r\n" );
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document.write( "Edwin
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