document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=61576>Question 61576</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I know when dividing fractions the second set you flip and then it becomes multiplication. But what if you have three sets??\r<BR>\n" );
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document.write( "8/21 / (-4/7) / 4/3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42383 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42383\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8/21 / (-4/7) / (4/3)<BR>\n" );
document.write( "Start \"flipping\" on the right side<BR>\n" );
document.write( "and keep flipping.)<BR>\n" );
document.write( "=(8/21)/(-4/7)*(3/4)<BR>\n" );
document.write( "Simplify:<BR>\n" );
document.write( "=(8/21)/(-3/7)<BR>\n" );
document.write( "Flip again:<BR>\n" );
document.write( "=(8/21)*(-7/3)<BR>\n" );
document.write( "Simplify:<BR>\n" );
document.write( "=(8/3)*(-1/3)<BR>\n" );
document.write( "= -8/9<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "stan H.<BR>\n" );
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