document.write( "Question 683918: The density of an object is W/V. If the density of an object is 5.25x10^-7 oz/ft^3?
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document.write( "and the volume is 2.2x10^3 ft^3, then find the weight?\r
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document.write( "Honestly i get to an answer 2.39 x10^-10 but i guess it's nor right\r
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document.write( "So i'm be happy if somebody can help me out? \n" );
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Algebra.Com's Answer #423802 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! D = W/V\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5.25x10^-7 = W/(2.2x10^3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(5.25x10^-7)*(2.2x10^3) = W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(5.25*2.2)x(10^-7*10^3) = W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(11.55)x(10^-4) = W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(1.155 x 10^1)x(10^-4) = W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1.155 x (10^1*10^-4) = W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1.155 x 10^-3 = W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "W = 1.155 x 10^-3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the weight is roughly 1.155 x 10^-3 ounces or 0.001155 ounces. \n" ); document.write( " |