document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=683805>Question 683805</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mixture Problem:\r<BR>\n" );
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document.write( "Question: Determine how many liters of 6% acid solution and how many liters of 12% acid solution should be mixed by a chemist to obtain 6 liter of 10% acid solution.\r<BR>\n" );
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document.write( "Ans. 3.6 ---> but i dont know the solution.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #423783 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=423783\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Determine how many liters of 6% acid solution and how many liters of 12% acid solution should be mixed by a chemist to obtain 6 liters of 10% acid solution. <BR>\n" );
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document.write( "Let x = amt of 12% solution<BR>\n" );
document.write( "the resulting amt is to be 6 liters, therefore:<BR>\n" );
document.write( "(6-x) = amt of 6% solution<BR>\n" );
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document.write( "A typical mixture equation, using the the decimal equiv of per cent<BR>\n" );
document.write( ".12x + .06(6-x) = .10(6)<BR>\n" );
document.write( ".12x + .36 - .06x = .6<BR>\n" );
document.write( ".12x - .06x = .6 - .36<BR>\n" );
document.write( ".06x = .24<BR>\n" );
document.write( "x = .24/.06<BR>\n" );
document.write( "x = 4 liters of the 12% solution<BR>\n" );
document.write( "and<BR>\n" );
document.write( "6 - 4 = 2 liters of 6% solution<BR>\n" );
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document.write( "Confirm this solution<BR>\n" );
document.write( ".12(4) + .06(2) = .10(6)<BR>\n" );
document.write( ".48 + .12 = .6; <BR>\n" );
document.write( "I don't know how they got a solution of 3.6 from this; anyway I wish you and your family a Happy Thanksgiving!!! </SPAN>\n" );
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