document.write( "Question 683824: 25 men can do a project in 20 days . 15 men leave the project after working for some timeand the remaining project is completed in the next 37 1/2 days . After how many days did those men leave ? \n" ); document.write( "
Algebra.Com's Answer #423770 by josmiceli(19441)\"\" \"About 
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Let \"+n+\" = number of days after starting when 15 men left
\n" ); document.write( "The 25 men work at a rate of ( 1 project ) / ( 20 days ), or \"+1%2F20+\"
\n" ); document.write( "What fraction of the project did they complete in \"+n+\" days?
\n" ); document.write( "\"+%281%2F20%29%2An+=+n%2F20+\" of the project
\n" ); document.write( "That means that the fraction of the project left to be done is
\n" ); document.write( "\"+1+-+n%2F20++\"
\n" ); document.write( "-------------
\n" ); document.write( "Now there are \"+20+-+15+=+5+\" men left to finish the project
\n" ); document.write( "If 25 men work at a rate of \"+1%2F20+\", then 5 men will be
\n" ); document.write( "5 times slower, or a rate of \"+%281%2F5%29%2A%281%2F20%29+=+1%2F100+\"
\n" ); document.write( "Now I can say
\n" ); document.write( "\"+1%2F100+=+%28+1+-+n%2F20+%29+%2F+37.5+\"
\n" ); document.write( "\"+.375+=+1+-+n%2F20+\"
\n" ); document.write( "Multiply both sides by \"+20+\"
\n" ); document.write( "\"+7.5+=+20+-+n+\"
\n" ); document.write( "\"+n+=+20+-+7.5+\"
\n" ); document.write( "\"+n+=+12.5+\"
\n" ); document.write( "The 15 men left after 12.5 days
\n" ); document.write( "check answer:
\n" ); document.write( "The original 25 men finished
\n" ); document.write( "\"+n%2F20+=+12.5%2F20+\"
\n" ); document.write( "\"+.625+\" as a fraction of the project
\n" ); document.write( "There was \"+1+-+.625+=+.375+\" left to do
\n" ); document.write( "The remaining 5 men work at a rate of \"+1%2F100+\"
\n" ); document.write( "\"+1%2F100+=+.375+%2F+37.5+\"
\n" ); document.write( "\"+37.5%2F100+=+.375+\"
\n" ); document.write( "OK\r
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