document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=683813>Question 683813</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 6-yard fishing line is cut into two pieces, as shown in the image below, where a = 6. Four times the length of the shorter piece is two times the length of the longer piece. Find the length of each piece.<BR>\n" );
document.write( "Also find the Equation to solve.\r<BR>\n" );
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document.write( "I am so lost. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #423743 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=423743\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The two pieces together are 6 yards, so<BR>\n" );
document.write( "x+y = 6<BR>\n" );
document.write( "...<BR>\n" );
document.write( "let x be the longer piece and y be the shorter piece<BR>\n" );
document.write( "4y = 2x<BR>\n" );
document.write( "...<BR>\n" );
document.write( "Rearrange x+y=6 as x = 6-y and substitute into 4y=2x<BR>\n" );
document.write( "4y = 2(6-y)<BR>\n" );
document.write( "Distribute the 2<BR>\n" );
document.write( "4y = 12 - 2y<BR>\n" );
document.write( "Add 2y to both sides<BR>\n" );
document.write( "4y + 2y = 12<BR>\n" );
document.write( "6y = 12<BR>\n" );
document.write( "Divide both sides by 6<BR>\n" );
document.write( "y = 2<BR>\n" );
document.write( "If y = 2, then x = 6-2 = 4<BR>\n" );
document.write( "...<BR>\n" );
document.write( "Therefore, the length of the two pieces are 2 yds and 4 yds<BR>\n" );
document.write( "..............................<BR>\n" );
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