document.write( "Question 683803: Help please in this problem: Mixture Problem\r
\n" ); document.write( "\n" ); document.write( "A radiator contains 25 liters of water and antifreeze solution, of which 60% is antifreeze. How much of this solution should be drained and replaced with water for new solution to be 40% antifreeze? \r
\n" ); document.write( "\n" ); document.write( "Ans. is 8.33 liters, but I dont know the solutions..
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Algebra.Com's Answer #423730 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The liters of antifreeze in the radiator is
\n" ); document.write( "\"+.6%2A25+=+15+\" liters
\n" ); document.write( "Let \"+x+\" = the number of liters to be drained and replaced with water
\n" ); document.write( "\"+.6x+\" = liters of antifreeze in the mixture that is drained
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\n" ); document.write( "The key is that you end up with the same liters you started with
\n" ); document.write( "\"+%28+15+-+.6x+%29+%2F+25+=+.4+\"
\n" ); document.write( "\"+15+-+.6x+=+.4%2A25+\"
\n" ); document.write( "\"+15+-+.6x+=+10+\"
\n" ); document.write( "\"+.6x+=+15+-+10+\"
\n" ); document.write( "\"+.6x+=+5+\"
\n" ); document.write( "\"+x+=+8.333+\" liters
\n" ); document.write( "------------------
\n" ); document.write( "check answer:
\n" ); document.write( "\"+%28+15+-+.6x+%29+%2F+25+=+.4+\"
\n" ); document.write( "\"+%28+15+-+.6%2A8.333+%29+%2F+25+=+.4+\"
\n" ); document.write( "\"+%28+15+-+5+%29+%2F+25+=+.4+\"
\n" ); document.write( "\"+10%2F25+=+.4+\"
\n" ); document.write( "\"+10+=+10+\"
\n" ); document.write( "OK
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