document.write( "Question 683786: graph the parabola with the following equation.. Give the focus coordinates, vertex coordinates, equation of directrix and one additional point on the curve.. \r
\n" ); document.write( "\n" ); document.write( "The equation is:
\n" ); document.write( "x= 1/16y^2 \n" ); document.write( "
Algebra.Com's Answer #423718 by lwsshak3(11628)\"\" \"About 
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graph the parabola with the following equation.. Give the focus coordinates, vertex coordinates, equation of directrix and one additional point on the curve..
\n" ); document.write( "The equation is:
\n" ); document.write( "x= 1/16y^2
\n" ); document.write( "**
\n" ); document.write( "rewrite equation:
\n" ); document.write( "y^2=16x
\n" ); document.write( "This is a parabola that opens rightwards.
\n" ); document.write( "Its standard form: (y-k)^2=4p(x-h), (h,k)=coordinates of the vertex
\n" ); document.write( "For given equation: y^2=16x
\n" ); document.write( "vertex: (0,0)
\n" ); document.write( "axis of symmetry: y=0
\n" ); document.write( "4p=16
\n" ); document.write( "p=4
\n" ); document.write( "focus=(4,0) (p-distance right of vertex on axis of symmetry)
\n" ); document.write( "directrix: x=4 ( (p-distance left of vertex on axis of symmetry)
\n" ); document.write( "2 points on curve: (1,4) and (1,-4)
\n" ); document.write( "see graph below:
\n" ); document.write( "y=(16x)^.5
\n" ); document.write( " \"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C%2816x%29%5E.5%2C-%2816x%29%5E.5%29+\" \n" ); document.write( "
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