document.write( "Question 683785: help please! a triangle has its vertices at (6,0), (5,3), and (-1,-4) find the equation of the line through the vertices parallel to the opposite side. \n" ); document.write( "
Algebra.Com's Answer #423717 by mananth(16946)\"\" \"About 
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(6,0), (5,3), and (-1,-4)\r
\n" ); document.write( "\n" ); document.write( "Let A (6,0), B(5,3), and C(-1,-4)be the vertices of the triangle\r
\n" ); document.write( "\n" ); document.write( "Let P,Q be the mid points of AB & AC respectively\r
\n" ); document.write( "\n" ); document.write( "PQ is parallel to BC\r
\n" ); document.write( "\n" ); document.write( "Determine co ordinates of P & Q by mid point formula\r
\n" ); document.write( "\n" ); document.write( "A (6,0), B(5,3), \r
\n" ); document.write( "\n" ); document.write( "Let P(x3,y3)\r
\n" ); document.write( "\n" ); document.write( "\"x3=+%286%2B5%29%2F2+=+11%2F2\"
\n" ); document.write( "\"y3=%283%2B0%29%2F2+=+3%2F2\"\r
\n" ); document.write( "\n" ); document.write( "p=((11/2),(3/2))\r
\n" ); document.write( "\n" ); document.write( "Similarly find co ordinates of Q the mid point of AC\r
\n" ); document.write( "\n" ); document.write( "Q=(x4,y4)
\n" ); document.write( "A (6,0), C(-1,-4)
\n" ); document.write( "\"x4=+%28-1%2B6%29%2F2=%285%2F2%29\"
\n" ); document.write( "\"y4=%28-4%2B0%29%2F2=+-2\"\r
\n" ); document.write( "\n" ); document.write( "Q=((5/2),(-2))\r
\n" ); document.write( "\n" ); document.write( "The equation of PQ \r
\n" ); document.write( "\n" ); document.write( "use formula \"%28%28y-y1%29%2F%28y1-y2%29%29=%28%28x-x1%29%2F%28x1-x2%29%29\"\r
\n" ); document.write( "\n" ); document.write( "p=((11/2),(3/2)), Q=((5/2),(-2))\r
\n" ); document.write( "\n" ); document.write( "equation of PQ -> \r
\n" ); document.write( "\n" ); document.write( "\"%28y-3%2F2%29%2F%287%2F2%29+=+%28x-%2811%2F2%29%29%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"3%28y-%283%2F2%29%29=%287%2F2%29%28x-%2811%2F2%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"3y-%289%2F2%29=7x%2F2-%2877%2F4%29\"\r
\n" ); document.write( "\n" ); document.write( "multiply equation by 4\r
\n" ); document.write( "\n" ); document.write( "\"12y-18=14x-77\"\r
\n" ); document.write( "\n" ); document.write( "14x-12y=59 is the equation of PQ\r
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