document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=61553>Question 61553</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534944949/algebrahomeworkh>Essential Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I am a Distance Education student. I am having trouble figuring out how to set this problem up to solve it. Thank you for your help :)\r<BR>\n" );
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document.write( "Problem: Lake Perris charges boaters different user fees depending on the horsepower (hp) rating of their engines. Zero-5 hp boaters are charged $5 per day, 6-50 hp $12, and over 50 hp $25 per day. If a total of 49 boaters used the lake on a certain day and paid $699 in fees, how many of each type boater used the lake, if there were ten more 6-50 hp boaters than zero-5 hp boaters? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42370 by </B><A HREF=/tutors/aboutme.mpl?userid=asha><B>asha(30)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=asha><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42370\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let there be x zero-5hp boaters<BR>\n" );
document.write( "there will be <BR>\n" );
document.write( "x+10 6-50hp boaters<BR>\n" );
document.write( "let there  be y boaters over 50hp<BR>\n" );
document.write( "given x+x+10+y=49<BR>\n" );
document.write( "2x + y =39    eqn.1<BR>\n" );
document.write( "zero hp boaters are charged 5$,6-50 hp boaters are charged 12$ and over 50hp boaters are charged25$<BR>\n" );
document.write( "the eqn. will be 5x+12(x+10)+25y=699<BR>\n" );
document.write( "5x+12x+120+25y=699<BR>\n" );
document.write( "17x+25y=699-120=579    eqn.2 <BR>\n" );
document.write( "multiply eqn.1 by 25, we get <BR>\n" );
document.write( "50x +25y =39*25 =975     eqn.3<BR>\n" );
document.write( "eqn.3-eqn.2 gives<BR>\n" );
document.write( "33x=975-579 =396<BR>\n" );
document.write( "x =396/33 =12 <BR>\n" );
document.write( "plugging x value in eqn,1 we get<BR>\n" );
document.write( "24+y =39<BR>\n" );
document.write( "y=39-24=15<BR>\n" );
document.write( "there are 12 zero hp boaters,22, 6-50 hp boaters and 15 boaters over 50hp.<BR>\n" );
document.write( "you can check the answers by plugging in the values in the equations.<BR>\n" );
document.write( "good luck !!!  </SPAN>\n" );
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