document.write( "Question 683633: a + 3b = 1,
\n" ); document.write( "2a - b = 1
\n" ); document.write( "

Algebra.Com's Answer #423634 by tsewaitung(11)\"\" \"About 
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a+3b=1----------(1)
\n" ); document.write( "2a-b=1----------(2)
\n" ); document.write( "from (2), we have
\n" ); document.write( " 2a-b=1
\n" ); document.write( " 2a=1+b
\n" ); document.write( " 2a-1=b---------(3)
\n" ); document.write( "by substituting (3) into (1), we have
\n" ); document.write( "a+3(2a-1)=1
\n" ); document.write( " a+6a-3=1
\n" ); document.write( " 7a=4
\n" ); document.write( " \"a=4%2F7\"
\n" ); document.write( "by substituting a=4/7 into (3), we have
\n" ); document.write( "2(4/7)-1=b
\n" ); document.write( " b=8/7-1
\n" ); document.write( " \"b=1%2F7\"
\n" ); document.write( "
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