document.write( "Question 683578: one side of right traingle is 12 cm long. The hyphotenuse is 3 cm more than twice as long as the other side. What are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #423625 by mananth(16946)\"\" \"About 
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one side = 12 cm
\n" ); document.write( "other side =x
\n" ); document.write( "hypotenuse = 2x+3\r
\n" ); document.write( "\n" ); document.write( "By Hypotenuse theorem\r
\n" ); document.write( "\n" ); document.write( "(2x+3)^2=x^2+12^2\r
\n" ); document.write( "\n" ); document.write( "4x^2+12x+9=x^2+144\r
\n" ); document.write( "\n" ); document.write( "3x^2+12x-135=0\r
\n" ); document.write( "\n" ); document.write( "/3
\n" ); document.write( "x^2+4x-45=0\r
\n" ); document.write( "\n" ); document.write( "x^2+9x-5x-45=0\r
\n" ); document.write( "\n" ); document.write( "x(x+9)-5(x+9)=0\r
\n" ); document.write( "\n" ); document.write( "(x+9)(x-5)=0\r
\n" ); document.write( "\n" ); document.write( "therefore x= -9 OR 5\r
\n" ); document.write( "\n" ); document.write( "ignore negative value\r
\n" ); document.write( "\n" ); document.write( "x=5 cm the other side\r
\n" ); document.write( "\n" ); document.write( "Hypotenuse = 2x+3.
\n" ); document.write( "Plug x=6
\n" ); document.write( "we get hypotenuse = 13\r
\n" ); document.write( "\n" ); document.write( "The dimensions are , 5,12,13\r
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