document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=683583>Question 683583</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two years ago, the sum of the ages of a boy and his sister is 20 years. Three years from now, their ages will differ by 10 years. Form a pair of linear equations and find their present age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #423622 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=423622\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the boy's age bex<BR>\n" );
document.write( "girls age be y\r<BR>\n" );
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document.write( "2 years ago their ages<BR>\n" );
document.write( "x-2 boy's age<BR>\n" );
document.write( "y-2 girls age\r<BR>\n" );
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document.write( "(x-2)+(y-2)=20<BR>\n" );
document.write( "x+y-4=20<BR>\n" );
document.write( "x+y=16...................(1)\r<BR>\n" );
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document.write( "3 years hence\r<BR>\n" );
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document.write( "their ages will be <BR>\n" );
document.write( "x+3 & y+3\r<BR>\n" );
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document.write( "(x+3)-(y+3)=10<BR>\n" );
document.write( "x-y=10.................(2)\r<BR>\n" );
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document.write( "Add (1) & (2)\r<BR>\n" );
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document.write( "2x= 26<BR>\n" );
document.write( "x= 13 the boy's age<BR>\n" );
document.write( "Girls age = 20-13=7\r<BR>\n" );
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document.write( "Their ages could be 13 & 7  </SPAN>\n" );
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