document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=683216>Question 683216</A>: <I><SPAN STYLE=\"word-break: break-all;\"> IF (-4,6) is on the terminal side of theta what are the 6 trig functions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #423608 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=423608\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> IF (-4,6) is on the terminal side of theta what are the 6 trig functions.<BR>\n" );
document.write( "visualize a circle with center at (0,0) where a point on the circle is at (-4,6)<BR>\n" );
document.write( "This gives a right triangle where the x-coordinate(-4) is the adjacent side and y-coordinate(6) is the opposite sidee. The hypotenuse then=&#8730;(4^2+6^2)=&#8730;(16+36)=&#8730;52<BR>\n" );
document.write( "6 trig functions as follows:<BR>\n" );
document.write( "sin=6/&#8730;52<BR>\n" );
document.write( "cos=-4/&#8730;52<BR>\n" );
document.write( "tan=-6/4<BR>\n" );
document.write( "csc=&#8730;52/6<BR>\n" );
document.write( "sec=-&#8730;52/4<BR>\n" );
document.write( "cot=-4/6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );