document.write( "Question 683434: Find all solutions to the equation:\r
\n" ); document.write( "\n" ); document.write( "x - 10 sqrt(x) + 25 = 0\r
\n" ); document.write( "\n" ); document.write( "I figured out via guess and check that x = 25 but how do i solve for it using algebra? also is there more then one answer?
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Algebra.Com's Answer #423584 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
use the theorem\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-y%29%5E2=x%5E2-2xy%2By%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x-10sqrt%28x%29+%2B+25+=+0+\"...in your case \"x\" is actually \"sqrt%28x%29\", and \"y\" is \"5\"\r
\n" ); document.write( "\n" ); document.write( "so, you have:\r
\n" ); document.write( "\n" ); document.write( "\"%28sqrt%28x%29-5%29%5E2+=+0+\"\r
\n" ); document.write( "\n" ); document.write( "this will be equal to zero if \"sqrt%28x%29-5+=+0+\"\r
\n" ); document.write( "\n" ); document.write( "so, we have\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28x%29=+5+\"....raise both sides to the power of two\r
\n" ); document.write( "\n" ); document.write( "\"%28sqrt%28x%29%29%5E2=+5%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "\"x=+25+\"\r
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