document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=682829>Question 682829</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help in this problem, thank you so much. \r<BR>\n" );
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document.write( "How can $42,000 be invested, part at 4% annual simple interest and the remainder at 10% annual simple interest, so that the interest earned by the two accounts is equal at the end of the year? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #423560 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=423560\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> total = x+y = 42000 ($ in x or 4% and $ in y or 10%)<BR>\n" );
document.write( ".04x = .10y  (interest from x, which is .04 times $ invested should be the same or = interest from \r<BR>\n" );
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document.write( "y, which is .10 times $ invested)<BR>\n" );
document.write( ".04(42000-y) = .10y  &#8658; substituting x = 42000-y <BR>\n" );
document.write( "1680 - .04y = .10y<BR>\n" );
document.write( "1680 = .10y + .04y<BR>\n" );
document.write( "1680 = .14y<BR>\n" );
document.write( "y = 12000 at 10% (CHECK: .10(12000) = 1200)<BR>\n" );
document.write( "x = 42000 - 12000 = 30000 at 4% (CHECK: .04(30000) = 1200)<BR>\n" );
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