document.write( "Question 682832: I need help in this problem, thank you. \r
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document.write( "If $2000 is invested at 10% simple annual interest, how much should be invested at 12% annual simple interest so that the total yearly income from both investments is $5000? \n" );
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Algebra.Com's Answer #423559 by ReadingBoosters(3246)![]() ![]() ![]() You can put this solution on YOUR website! x = 2000 at 10% \n" ); document.write( ".1x + .12y = 5000 \n" ); document.write( ".1(2000) + .12y = 5000 ⇒ substitute 2000 for x \n" ); document.write( "200 + .12y = 5000 \n" ); document.write( ".12y = 5000 - 200 \n" ); document.write( ".12y = 4800 \n" ); document.write( "y = 40,000 \n" ); document.write( " \n" ); document.write( " |