document.write( "Question 682832: I need help in this problem, thank you. \r
\n" ); document.write( "\n" ); document.write( "If $2000 is invested at 10% simple annual interest, how much should be invested at 12% annual simple interest so that the total yearly income from both investments is $5000?
\n" ); document.write( "

Algebra.Com's Answer #423559 by ReadingBoosters(3246)\"\" \"About 
You can put this solution on YOUR website!
x = 2000 at 10%
\n" ); document.write( ".1x + .12y = 5000
\n" ); document.write( ".1(2000) + .12y = 5000 ⇒ substitute 2000 for x
\n" ); document.write( "200 + .12y = 5000
\n" ); document.write( ".12y = 5000 - 200
\n" ); document.write( ".12y = 4800
\n" ); document.write( "y = 40,000
\n" ); document.write( "
\n" ); document.write( "
\n" );